# Best answer: What is the mole percent O2 in the mixture?

Contents

## What is the mole percentage of O2?

Mole percent of oxygen = x1/(x1+x2) *100 = 1/(1+0.5) *100 = 66.66 %…….. (c)

## How do you find the mole percent of a mixture?

Multiplying the mole fraction by 100 gives the mole percentage, also referred as amount/amount percent (abbreviated as n/n%). For general chemistry, all the mole percents of a mixture add up to 100 mole percent. We can easily convert mole percent back to mole fraction by dividing by 100.

## What is the mole percentage of O2 in a mixture of 7g?

the mole percentage of O2 in a mixture of 7g of N2 and 8g of O2 is? (ans:50%)

## What is the mole percentage of O2 in a mixture of 7 grams and N2 and AG of O2?

The mole percentage of oxygen in a mixture of 7g N2 and 8g O2 is : 25.

## What is the amount of oxygen in 3.6 moles of water?

So, if in one mole of water, 16 g of oxygen atom is present. Then, in 3.6 moles of water, the mass of oxygen present will be 3.6×16=57.6g. Therefore, the amount of oxygen present in 3.6 g water is option (B)- 57.6 g.

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## What is the mole formula?

If you know the particles, moles, or grams of a substance, you can calculate the other two measurements by using the following equation: 1 mole = 6.022 × 1023 particles/mol = formula weight expressed in grams. … The mass of one mole (6.02 X 1023) of chromium atoms is 51.9961 grams.

## How do I calculate moles?

To convert between grams and moles, you would use the substance’s molar mass. To go from grams to moles, divide the grams by the molar mass. 600 g58.443 g/mol = 10.27 mol of NaCl. It has been found that 1 mol of any gas at STP (Standard Temperature and Pressure = 0 °C and 1 atm) occupies 22.4 L.

## What is the mole fraction of c3h5 OH 3 in a solution of 36g of water and 46g of glycerine is?

Thus, the mole fraction of \${C_3}{H_5}{(OH)_3}\$ in a solution of 36 g of water and 46 g glycerine is 0.2.

## What is the mass and charge of one mole of electron?

Hence the mass of 1 mole electron of electrons is \$5.48 times {10^{ – 7}}\$Kg. -Now, we will calculate the charge of 1 mole electrons. Hence the charge of 1 mole of electrons will be \$9.65 times {10^4}\$C.

## What is the percentage of oxygen in NaOH?

Note: The percent creation of NaOH , otherwise called sodium hydroxide, is 57.48 percent sodium, 40% oxygen, and 2.52 percent hydrogen. Computing.

## What is the molar mass of o2?

We know that there’s a colligative relation where the density of the mixture is related to the mole fraction of the components: D = XA×d1 + XB×d2 the other fact is that the sum of the molar fractions is unity: XA+XB = 1 so we have two variables and two equations.

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